/*
    函数声明演示
*/
#include <stdio.h>
double add(double, double);
int main() {
    printf("求和结果是%g\n",add(3,7));
    return 0;
}
/*int add(int num, int num1) {
    return num + num1;
}*/
double add(double num, double num1) {
    return num + num1;
}
